A protection is connected between the DC power supply and the load. Loads below 12V and above 80V will stop working, and the load will stop working when the current exceeds 50A (because the working current of the load is not fixed). I want to use a 120A high-current relay to control the switch. I don’t know what to use. I’m a novice on designing circuits. I have limited knowledge. The forum is like a cloud of experts. So I came up to ask a question. If the circuit can have a self-recovery function, it’s best to wait a few seconds after the overcurrent. Whether it’s over-current, if the over-current continues to power off, if the relay operates normally, it’s best if it can display the current with a digital tube. I know that if the price is too high, I have to write a program. After all, I need it. One, I don't have that strength, and I don't know what to express. I would like to trouble you all masters to point out, thank you very much. (A total of 11 points are provided) The above circuit does not need to be designed as a finished product, which means that a circuit diagram is needed because it needs to be combined with other circuits to make a PCB board. In other words, just ask the master to test and provide the circuit diagram.
Karena ポストする July 22, 2020
Connect the current and voltage sensor, and the single-chip microcomputer can detect it.
Rush ポストする July 22, 2020
Where to continue to measure the overcurrent after the overcurrent is disconnected? This is an impossible logic that cannot be realized. Assuming that the overcurrent is not caused by equipment damage, after a delay, the automatic recovery can continue to detect, if the equipment is damaged and continue to be powered on, it may happen More dangerous, not feasible.
Tiberius ポストする July 22, 2020
The easiest way is to learn from the protection circuit of the inverter.
