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Regarding the 3.7V to 5V circuit.

Hardware design
9月 17, 2020 by Fitzsimmons 434

The chip is TPS61032. Because of the test, the input is a 5V10A switching power supply.

When this chip is loaded with 300MA, everything is normal and it outputs 5V stably.

When the load is 1.2A, the output is only 3.6V, and the input voltage is still 5V, and it has been slowly heating up to 45 degrees. I was afraid of burning, so I turned it off.

Because I need a 3.7V to 5v2A circuit, is there a way to solve the temperature rise and voltage drop? Adding a heat sink, is it useless?

すべてのコメント

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Hickman ポストする September 17, 2020

Note that the maximum current in the specification refers to the current of the internal switch tube, not the output current.

If 3.6V rises to 5V, it is recommended to use a circuit with a switch tube greater than 8A if the output is 2A.

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Hicks ポストする September 17, 2020

The L1 wire should be thick enough and the resistance should be small enough.

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Shockley ポストする September 17, 2020

The maximum output of this chip is 1A, and the efficiency of 2A is very low.

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