<div>What is the function of (addr 256)<<1? How to achieve it?
What is the function of (addr/256)<<1? How to achieve it? <div>What is the function of (addr 256)<<1? How to achieve it?
Is adding up the parameters of this statement equal to sending the two parameters separately?
Gwyneth ポストする December 3, 2020
(addr/256)<<1
Equivalent to
(addr/256) * 2
Sian ポストする December 3, 2020
The following is the meaning of "page turning", because 24c4-24c16 are single-byte addressing. When the address exceeds 1 byte (255), a page needs to be replaced. The ones above 24c32 are double-byte addressing, so there is no need to do this.
Katerina ポストする December 3, 2020
Very simple, because the address of the IIC is the upper 7 bits, and the lowest bit of the address sent is the R/W bit.
When using the device address + data address to send, the data address is bound to move one bit to the left.
Sammy ポストする December 3, 2020
Isn't 0xA0 the device address? Doesn't it turn to another AT24Cxx if it turns to 0xA1?
